URI의 마지막 경로 세그먼트를 얻는 방법

URI의 마지막 경로 세그먼트를 얻는 방법

---

나는 입력에 URI. 마지막 경로 세그먼트를 얻는 방법은 무엇입니까? 제 경우에는 신분증인가요?

이것은 내 입력 URL입니다

String uri = "http://base_path/some_segment/id"

그리고 나는 이것으로 시도한 ID를 얻어야합니다

String strId = "http://base_path/some_segment/id";
strId=strId.replace(path);
strId=strId.replaceAll("/", "");
Integer id =  new Integer(strId);
return id.intValue();

그러나 그것은 작동하지 않으며 확실히 그것을하는 더 나은 방법이 있습니다.

---

당신이 찾고있는 것입니다 :

URI uri = new URI("http://example.com/foo/bar/42?param=true");
String path = uri.getPath();
String idStr = path.substring(path.lastIndexOf('/') + 1);
int id = Integer.parseInt(idStr);

대안으로

URI uri = new URI("http://example.com/foo/bar/42?param=true");
String[] segments = uri.getPath().split("/");
String idStr = segments[segments.length-1];
int id = Integer.parseInt(idStr);

---

import android.net.Uri;
Uri uri = Uri.parse("http://example.com/foo/bar/42?param=true");
String token = uri.getLastPathSegment();

---

이를 수행하는 간단한 방법은 다음과 같습니다.

public static String getLastBitFromUrl(final String url){
    // return url.replaceFirst("[^?]*/(.*?)(?:\\?.*)","$1);" <-- incorrect
    return url.replaceFirst(".*/([^/?]+).*", "$1");
}

테스트 코드 :

public static void main(final String[] args){
    System.out.println(getLastBitFromUrl(
        "http://example.com/foo/bar/42?param=true"));
    System.out.println(getLastBitFromUrl("http://example.com/foo"));
    System.out.println(getLastBitFromUrl("http://example.com/bar/"));
}

산출:

42
푸
바

설명:

.*/      // find anything up to the last / character
([^/?]+) // find (and capture) all following characters up to the next / or ?
         // the + makes sure that at least 1 character is matched
.*       // find all following characters


$1       // this variable references the saved second group from above
         // I.e. the entire string is replaces with just the portion
         // captured by the parentheses above

---

나는 이것이 오래되었다는 것을 알고 있지만 여기의 해결책은 다소 장황 해 보입니다. URL또는 URI다음 이 있으면 쉽게 읽을 수있는 한 줄짜리 줄입니다 .

String filename = new File(url.getPath()).getName();

또는 다음이있는 경우 String:

String filename = new File(new URL(url).getPath()).getName();

---

Java 8을 사용 중이고 파일 경로의 마지막 세그먼트를 원하는 경우 수행 할 수 있습니다.

Path path = Paths.get("example/path/to/file");
String lastSegment = path.getFileName().toString();

당신이 http://base_path/some_segment/id할 수있는 것과 같은 URL이 있다면 .

final Path urlPath = Paths.get("http://base_path/some_segment/id");
final Path lastSegment = urlPath.getName(urlPath.getNameCount() - 1);

---

In Java 7+ a few of the previous answers can be combined to allow retrieval of any path segment from a URI, rather than just the last segment. We can convert the URI to a java.nio.file.Path object, to take advantage of its getName(int) method.

Unfortunately, the static factory Paths.get(uri) is not built to handle the http scheme, so we first need to separate the scheme from the URI's path.

URI uri = URI.create("http://base_path/some_segment/id");
Path path = Paths.get(uri.getPath());
String last = path.getFileName().toString();
String secondToLast = path.getName(path.getNameCount() - 2).toString();

To get the last segment in one line of code, simply nest the lines above.

Paths.get(URI.create("http://base_path/some_segment/id").getPath()).getFileName().toString()

To get the second-to-last segment while avoiding index numbers and the potential for off-by-one errors, use the getParent() method.

String secondToLast = path.getParent().getFileName().toString();

Note the getParent() method can be called repeatedly to retrieve segments in reverse order. In this example, the path only contains two segments, otherwise calling getParent().getParent() would retrieve the third-to-last segment.

---

In Android

Android has a built in class for managing URIs.

Uri uri = Uri.parse("http://base_path/some_segment/id");
String lastPathSegment = uri.getLastPathSegment()

---

You can use getPathSegments() function. (Android Documentation)

Consider your example URI:

String uri = "http://base_path/some_segment/id"

You can get the last segment using:

List<String> pathSegments = uri.getPathSegments();
String lastSegment = pathSegments.get(pathSegments.size - 1);

lastSegment will be id.

---

If you have commons-io included in your project, you can do it without creating unecessary objects with org.apache.commons.io.FilenameUtils

String uri = "http://base_path/some_segment/id";
String fileName = FilenameUtils.getName(uri);
System.out.println(fileName);

Will give you the last part of the path, which is the id

---

I'm using the following in a utility class:

public static String lastNUriPathPartsOf(final String uri, final int n, final String... ellipsis)
  throws URISyntaxException {
    return lastNUriPathPartsOf(new URI(uri), n, ellipsis);
}

public static String lastNUriPathPartsOf(final URI uri, final int n, final String... ellipsis) {
    return uri.toString().contains("/")
        ? (ellipsis.length == 0 ? "..." : ellipsis[0])
          + uri.toString().substring(StringUtils.lastOrdinalIndexOf(uri.toString(), "/", n))
        : uri.toString();
}

---

Get URL from URI and use getFile() if you are not ready to use substring way of extracting file.

참고URL : https://stackoverflow.com/questions/4050087/how-to-obtain-the-last-path-segment-of-an-uri